# How can I extract all values from a dictionary in Python?

I have a dictionary `d = {1:-0.3246, 2:-0.9185, 3:-3985, ...}`.

How do I extract all of the values of `d` into a list `l`?

## Here is Solutions:

We have many solutions to this problem, But we recommend you to use the first solution because it is tested & true solution that will 100% work for you.

### Solution 1

If you only need the dictionary keys `1`, `2`, and `3` use: `your_dict.keys()`.

If you only need the dictionary values `-0.3246`, `-0.9185`, and `-3985` use: `your_dict.values()`.

If you want both keys and values use: `your_dict.items()` which returns a list of tuples `[(key1, value1), (key2, value2), ...]`.

### Solution 2

Use `values()`

``````>>> d = {1:-0.3246, 2:-0.9185, 3:-3985}

>>> d.values()
<<< [-0.3246, -0.9185, -3985]
``````

### Solution 3

For Python 3, you need:

``````list_of_dict_values = list(dict_name.values())
``````

### Solution 4

If you want all of the values, use this:

``````dict_name_goes_here.values()
``````

If you want all of the keys, use this:

``````dict_name_goes_here.keys()
``````

IF you want all of the items (both keys and values), I would use this:

``````dict_name_goes_here.items()
``````

### Solution 5

For nested dicts, lists of dicts, and dicts of listed dicts, … you can use

``````from typing import Iterable

def get_all_values(d):
if isinstance(d, dict):
for v in d.values():
yield from get_all_values(v)
elif isinstance(d, Iterable): # or list, set, ... only
for v in d:
yield from get_all_values(v)
else:
yield d
``````

An example:

``````d = {'a': 1, 'b': {'c': 2, 'd': [3, 4]}, 'e': [{'f': 5}, {'g': set([6, 7])}]}
list(get_all_values(d)) # returns [1, 2, 3, 4, 5, 6, 7]
``````

PS: Yes, I love `yield`. 😉

### Solution 6

Call the `values()` method on the dict.

### Solution 7

If you want all of the values, use this:

``````dict_name_goes_here.values()
``````

### Solution 8

Code of python file containing dictionary

``````dict={"Car":"Lamborghini","Mobile":"iPhone"}
print(dict)
``````

If you want to print only values (instead of key) then you can use :

``````dict={"Car":"Lamborghini","Mobile":"iPhone"}
for thevalue in dict.values():
print(thevalue)
``````

This will print only values instead of key from dictionary

Bonus : If there is a dictionary in which values are stored in list and if you want to print values only on new line , then you can use :

``````dict={"Car":["Lamborghini","BMW","Mercedes"],"Mobile":["Iphone","OnePlus","Samsung"]}
nd = [value[i] for value in dict.values()
for i in range(2)]
print(*nd,sep="\n")
``````

### Solution 9

I know this question been asked years ago but its quite relevant even today.

``````>>> d = {1:-0.3246, 2:-0.9185, 3:-3985}
>>> l = list(d.values())
>>> l
[-0.3246, -0.9185, -3985]
``````

### Solution 10

``````d = <dict>
values = d.values()
``````

### Solution 11

To see the keys:

``````for key in d.keys():
print(key)
``````

To get the values that each key is referencing:

``````for key in d.keys():
print(d[key])
``````

Add to a list:

``````for key in d.keys():
mylist.append(d[key])
``````

### Solution 12

Pythonic duck-typing should in principle determine what an object can do, i.e., its properties and methods. By looking at a dictionary object one may try to guess it has at least one of the following: `dict.keys()` or `dict.values()` methods. You should try to use this approach for future work with programming languages whose type checking occurs at runtime, especially those with the duck-typing nature.

### Solution 13

``````dictionary_name={key1:value1,key2:value2,key3:value3}
dictionary_name.values()
``````

### Solution 14

Normal Dict.values()

will return something like this

dict_values([‘value1’])

dict_values([‘value2’])

If you want only Values use

• Use this

list(Dict.values()) # Under the List

Note: Use and implement solution 1 because this method fully tested our system.
Thank you 🙂

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