Create an array with all numbers from min to max without a loop

I have two numbers, min and max, and I want to create an array that contains all number between them (including min and max).

The most obvious approach is to use a for loop for this, and push the single values onto an array. Nevertheless, this seems to be a quite naive approach, i.e. it’s imperative programming.

Now I was thinking of how to create such an array in a more functional style. Basically, something such as the reverse of a reduce function: Instead of reducing an array to a number, building up an array from two numbers.

How could I do this? What is a functional approach to solve this problem?

Basically, I’m thinking of something such as 10..20 in some other languages. What’s the most elegant equivalent for this in JavaScript?

Here is Solutions:

We have many solutions to this problem, But we recommend you to use the first solution because it is tested & true solution that will 100% work for you.

Solution 1

Inspired by this

var min = 3, max = 10;
var x = Array.apply(null, {length: max + 1}).map(, Number).slice(min);
// [ 3, 4, 5, 6, 7, 8, 9, 10 ]

The optimum version

var min = 3, max = 10;
var x = Array.apply(null, {length: max + 1 - min}).map(function(_, idx) {
    return idx + min;
// [ 3, 4, 5, 6, 7, 8, 9, 10 ]

Solution 2

You can think of a “functional” definition of range:

range(low, hi) = [], if low > hi
range(low, hi) = [low] (+) range(low+1,hi), otherwise,

which leads to the JS definition:

function range(low,hi){
  function rangeRec(low, hi, vals) {
     if(low > hi) return vals;
     return rangeRec(low+1,hi,vals);
  return rangeRec(low,hi,[]);

Solution 3

A one line way. Inspired by How to create an array containing 1…N.

Array.from({length: max-min+1}, (_, i) => i + min);

Initiate an array from a computed length based on max and min. Then map each index value by a function which is "index + min". The reference is here.


const min = 12;
const max = 20;
const arr = Array.from({length: max-min+1}, (_, i) => i + min);

Solution 4

If you have harmony generators you can use this:

function* range(lorange,hirange){
  var n = lorange;
  while (n <= hirange){
    yield n++;

rval= range(3,6);

Now you can :

  1. Use the for-of comprehension for iterators as substitute of array

    for (i of rval)
  2. Or you can use it to create an array like you want

    rarray = [];
    for (i of rval)

Solution 5

Might be late to the party, but, based on this (es6)

const rangexy = (start, end) => Array.from({length: (end+1 - start)}, (v, k) => k + start);

Note: Use and implement solution 1 because this method fully tested our system.
Thank you 🙂

All methods was sourced from or, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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